Seems I was just not meant to find my own shiny in this game.
Multiple fishing chains of 100+ & can't seem to chain past about 7 with the radar.
Following the guide as best I can, I also still get nothing biting sometimes even with Suction Cups active.
(✖╭╮✖)
Anyone have a statistic for getting a shiny through SR?
Edit: Finally fished up a shiny Relicanth somewhere between a 30-50 chain ^__^
If you could though it'd be 1/4092, same as the wild chance
Woah, 1/4092? Is that official or just speculation? There does seem to be more shinies this generation, but 1/4092 is twice the odds of every other game.
i believe someone had done the math on the odds and its highly likely the odds have been doubled. i could be wrong but im pretty sure i read that somewhere
I saw that Serebii posted those odds on his X/Y Shiny page, so there must be a decent amount of evidence to support it. That's pretty crazy that the game designers would just double it, I wonder if they changed the Masuda Method odds as well. I'm also curious what the official odds of the Friend Safari will be, as a ton of people are having a lot of luck with those too.
I thought it just meant Random Encounter (No chaining, MM breeding, or anything), and that they were just boasting.
By the way, where's better to chain for Scatterbug? Route 2 or Santalune Forest?
I saw that Serebii posted those odds on his X/Y Shiny page, so there must be a decent amount of evidence to support it. That's pretty crazy that the game designers would just double it, I wonder if they changed the Masuda Method odds as well. I'm also curious what the official odds of the Friend Safari will be, as a ton of people are having a lot of luck with those too.
It's all technical coding stuff, but I'll try to explain to the best of my knowledge. Well, you probably already know a Pokemon's shininess is determined by their Shiny ID vs the player's shiny ID, if these are the same it will result in a shiny. In the older games the number that determines if a Pokemon was Shiny was 0 - 7, so 8 rolls. In X and Y the number can be from 0 - 15, 16 rolls. Thus doubling chances.